3+(x-6)^1/2=(x+9)^1/2

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Solution for 3+(x-6)^1/2=(x+9)^1/2 equation: 


x in (-oo:+oo)

((x-6)^1)/2+3 = ((x+9)^1)/2 // - ((x+9)^1)/2

((x-6)^1)/2-(((x+9)^1)/2)+3 = 0

(x-6)/2-((x+9)/2)+3 = 0

(x-6)/2+(-1*(x+9))/2+3 = 0

(x-6)/2+(-1*(x+9))/2+(2*3)/2 = 0

x-1*(x+9)+2*3-6 = 0

6-15 = 0

-9 = 0

-9/2 = 0

-9/2 = 0 // * 2

-9 = 0

x belongs to the empty set

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